Matematika feladatok
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#101
[3(x^2+8x)]' = [3x^2+24x]' = 6x+24
[(x-4)^2]' = [x^2-8x+16]' = 2x-8
vagyis
f'*g = 6x+24*(x^2-8x+16)
f*g' = (3x^2+24x)*2x-8
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